RUSSIAN JOURNAL OF EARTH SCIENCES VOL. 8, ES1002, doi:10.2205/2005ES000185, 2006
[102] Given: ( j, l ) are the latitude and longitude of the site where paleomagnetic samples were collected; ( F, L ) denote the latitude and the longitude of the paleomagnetic pole calculated using the dipole law; G2 and G3 are the quadrupolar and octupolar coefficients ( G2 = g02/g01; G3=g03/g01 ).
[103] Required to find ( F32, L32 ) are the latitude and longitude of the respective paleomagnetic pole accounting for the contribution of the non-dipole components.
[104] Solution: (1) Knowing the coordinates of the sampling site and the coordinates of the pole, we found D and I, which are the declination and inclination of the old geomagnetic field at the sampling site:
[105] (2) Using the expression
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where I is the inclination of the magnetic field at the site with paleolatitude j m32, we found a new paleolatitude of the sampling site j m32 taking into account the contribution of the non-dipole components.
[106] (3) Using the conventional technique, we calculated the new coordinates of the paleomagnetic pole:
or
where
[107] (4) As a result, we had the paleomagnetic pole ( F32, L32 ) calculated taking into account the geomagnetic field of the G2 and G3 non-dipole components.
Citation: 2006), New paleomagnetic data for the Permian-Triassic Trap rocks of Siberia and the problem of a non-dipole geomagnetic field at the Paleozoic-Mesozoic boundary, Russ. J. Earth Sci., 8, ES1002, doi:10.2205/2005ES000185.
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